The Dirty Dozen - SOLD

[Peter_Spaeth]

How many combinations of 5 cards could be made from this group of 12?

[Mike (18colt)]

Originally Posted by Peter_Spaeth

How many combinations of 5 cards could be made from this group of 12?

I believe it's 792 combos. Statistically, 12 choose 5, which would be 12!/[(5!)(7!)].

[Peter_Spaeth]

Originally Posted by Mike (18colt)

I believe it's 792 combos. Statistically, 12 choose 5, which would be 12!/[(5!)(7!)].

Indeed. Dividing by 7! accounts for only choosing 5 items of the 12, and dividing by 5! accounts for the fact that within the group of 5 sequence doesn't matter.

[frankbmd]

Originally Posted by Peter_Spaeth

How many combinations of 5 cards could be made from this group of 12?

Originally Posted by Mike (18colt)

I believe it's 792 combos. Statistically, 12 choose 5, which would be 12!/[(5!)(7!)].

Originally Posted by Peter_Spaeth

Indeed. Dividing by 7! accounts for only choosing 5 items of the 12, and dividing by 5! accounts for the fact that within the group of 5 sequence doesn't matter.

I appreciate the responses so much, having majored in Mathemagic, that I will pose another question.

How many combinations of the 12 cards shown can be made to form a Baker's Dozen?

Answer correctly and you can purchase all 12, or is it 13, for $40 shipped.

Please answer only if you intend to purchase.

[scottglevy]

I’m gonna go with this answer. It depends on whether you are seeking combinations or permutations.

Permutations = 13! (13 - 12)! = 6,227,020,800
Combinations = 13! 12! × (13 - 12)! = 13

Best
SGL

[frankbmd]

Originally Posted by scottglevy

I’m gonna go with this answer. It depends on whether you are seeking combinations or permutations.

Permutations = 13! (13 - 12)! = 6,227,020,800
Combinations = 13! 12! × (13 - 12)! = 13

Best
SGL

Not quite right.

[Peter_Spaeth]

If I were to answer I would answer 0.