Vintage Set Group Break Idea! Input Needed!

[ZachS]

Originally Posted by ocjack

If I'm the only one to have this question, please feel free to delete this post.

But can someone explain what is going on? I've never heard of group breaks.

Thanks.

Using the example of the 1955 Topps set there are 206 cards total in the set... that means 206 slots available for sale.

There is a set price per slot and you can buy multiple slots.

Let's say you buy 5 slots at $25 per slot ($125 total). Your name will be put in the group 5 times (once per slot).

All names go into a randomizer... that's a program that will randomly put each name next to a number (in this case 1-206)

You will end up with 5 numbers between 1 and 206 selected w/ the randomizer program.

For example the randomizer puts your name next to numbers 11, 32, 47, 138, 198 in which case you'd get Fain, McGhee, Aaron, Hebert, and Berra.

That means you would end up with those card numbers from the set.

You could end up with 4 commons and a HOFer and make out pretty well or you could end spending $125 for 5 commons... it's all a gamble.

That's about as far as I can break it down without drawing pictures. Hopefully it makes sense.

[brewing]

If multiple slots were purchased, would shipping be combined?

[ocjack]

@ZackS

Thanks. That explained it very well. Appreciate your taking the time.

[mattsey9]

Interested in a spot.

[autocentral]

Originally Posted by brewing

If multiple slots were purchased, would shipping be combined?

Shipping would be combined if you have multiple spots. Also there will be some discounts depending on how many spots you buy. But that will be determined once we figure out the monetary dynamics of the break.

-Nick

[autocentral]

Originally Posted by ZachS

Using the example of the 1955 Topps set there are 206 cards total in the set... that means 206 slots available for sale.

There is a set price per slot and you can buy multiple slots.

Let's say you buy 5 slots at $25 per slot ($125 total). Your name will be put in the group 5 times (once per slot).

All names go into a randomizer... that's a program that will randomly put each name next to a number (in this case 1-206)

You will end up with 5 numbers between 1 and 206 selected w/ the randomizer program.

For example the randomizer puts your name next to numbers 11, 32, 47, 138, 198 in which case you'd get Fain, McGhee, Aaron, Hebert, and Berra.

That means you would end up with those card numbers from the set.

You could end up with 4 commons and a HOFer and make out pretty well or you could end spending $125 for 5 commons... it's all a gamble.

That's about as far as I can break it down without drawing pictures. Hopefully it makes sense.

Thank you for the help in explaining the concept. I really appreciate it.

-Nick