The Saga of "54" and the Truth - Post #120

[novakjr]

Originally Posted by peterb69

Emc2 = 54

Interesting. In that equation. There appears to be multiple possiblities for the values of e m and c. They can all equal 3, although I'd lean toward that being unlikely, as it would've been more simple to assign a cubed singular varible. Although it is possible assuming that e, c and m could all be the same number, if they were representing different theoretical specifics. The more likely scenario being any combination that has one of them equaling 1, another equaling 3, and the third equaling 9..

In the context of that equation e definitely does not equal mc², in term of a fully whole number valued equation.

Unless, your large 2 represented "square". Then we're left with a different set of possibilities all-together. C could equal 1, while e and m could be interchangeably represent the numbers 2 and 27, 1 and 54, 3 and 18, or 6 and 9. It's possible that c could equal 3, while e and m represent 1 and 6, or 2 and 3. C could be represented by either positive or negative numbers. As it pertains to e and m. They could only both be negative or both be positive, but not 1 of each..

Again, we are not left with a solely whole number valued equation that can make e=mc².

Assuming that both emc2=54 AND e=mc², or emc²=54 and e=mc², fractions and decimals are the only possibilities.

[tschock]

I think it was from a 12 year old named Adam who was missing #54 from his set. He was definitely into older police partner TV shows like "DragNet" and "Car(d) 54 Where are you?".

[frankbmd]

Originally Posted by novakjr

Interesting. In that equation. There appears to be multiple possiblities for the values of e m and c. They can all equal 3, although I'd lean toward that being unlikely, as it would've been more simple to assign a cubed singular varible. Although it is possible assuming that e, c and m could all be the same number, if they were representing different theoretical specifics. The more likely scenario being any combination that has one of them equaling 1, another equaling 3, and the third equaling 9..

In the context of that equation e definitely does not equal mc², in term of a fully whole number valued equation.

Unless, your large 2 represented "square". Then we're left with a different set of possibilities all-together. C could equal 1, while e and m could be interchangeably represent the numbers 2 and 27, 1 and 54, 3 and 18, or 6 and 9. It's possible that c could equal 3, while m and c represent 1 and 6, or 2 and 3. C could be represented by either positive or negative numbers. As it pertains to e and m. They could only both be negative or both be positive, but not 1 of each..

Again, we are not left with a solely whole number valued equation that can make e=mc².

Assuming that both emc2=54 AND e=mc², or emc²=54 and e=mc², fractions and decimals are the only possibilities.

David, I used the numbers on my telephone keypad, squared the c and multiplied and came up with 72, so if Emc2 is correct, welcome all to

Net72

[novakjr]

Originally Posted by frankbmd

David, I used the numbers on my telephone keypad, squared the c and multiplied and came up with 72, so if Emc2 is correct, welcome all to

Net72

The first portion of that was assuming that the larger 2 was just a 2... The second portion addressed as if it represented a "square".

[frankbmd]

Originally Posted by novakjr

I could be wrong. But I'm pretty sure that the way it is written, you would square the value of c before doing anything else with it. Otherwise it would need to be written as (emc)²

3 * 6 * (2*2) = 72

Don't screw around with a math major.

[novakjr]

Originally Posted by frankbmd

3 * 6 * (2*2) = 72

Don't screw around with a math major.

Yes, yes. you confused the hell out of me for a moment there. I see the error, I accidentally assigned c twice in one of those possibilities. I'll go back and fix it.

I've just been playing around anyways. Gimme a break lol.. It's probably been 16 years since I've even seriously entertained a math problem. The last time would've been AP Calculus during my Junior year of HS.. I won't count my semester in college, because I was pretty much drunk or hungover the whole time..

[novakjr]

Originally Posted by frankbmd

3 * 6 * (2*2) = 72

Don't screw around with a math major.

Even with my mistake, I don't see a possibility that I listed which e,m and c would result in any combination of 3, 6 and 2 together.

NEVERMIND. I get it now. It wasn't anything I did. I misread your reasoning, and it went straight over my head..

[BleedinBlue]

The answer is really much easier than that guys.

54 cards is the tipping point for most people who tackle the monster. Many, many people eventually try to defeat the monster and nearly all of them slink away with their tails between their legs. But careful analysis by Ted and many other long time collectors identified the number 54 as the point of no return. Once a collector had acquired their 54th card from the T206 set they were once and forever ensnared in the monsters NET.

Or, at the kickoff meeting for the Vintage Card Collectors Forum, each member was given one vote when electing a president. While there were only 12 people in attendance, it was quickly noted that there were 54 votes cast. A quick investigation discovered the discrepancy resulted when each of the Bruce Dorskinds had voted separately.

[Big Six]

Originally Posted by BleedinBlue

The answer is really much easier than that guys.

Or, at the kickoff meeting for the Vintage Card Collectors Forum, each member was given one vote when electing a president. While there were only 12 people in attendance, it was quickly noted that there were 54 votes cast. A quick investigation discovered the discrepancy resulted when each of the Bruce Dorskinds had voted separately.

If this isn't the reason Net54 got it's name, well, it should be...

[Leon]

Originally Posted by BleedinBlue

The answer is really much easier than that guys.


Or, at the kickoff meeting for the Vintage Card Collectors Forum, each member was given one vote when electing a president. While there were only 12 people in attendance, it was quickly noted that there were 54 votes cast. A quick investigation discovered the discrepancy resulted when each of the Bruce Dorskinds had voted separately.

that was good...