[frankbmd]

Originally Posted by novakjr

Interesting. In that equation. There appears to be multiple possiblities for the values of e m and c. They can all equal 3, although I'd lean toward that being unlikely, as it would've been more simple to assign a cubed singular varible. Although it is possible assuming that e, c and m could all be the same number, if they were representing different theoretical specifics. The more likely scenario being any combination that has one of them equaling 1, another equaling 3, and the third equaling 9..

In the context of that equation e definitely does not equal mc², in term of a fully whole number valued equation.

Unless, your large 2 represented "square". Then we're left with a different set of possibilities all-together. C could equal 1, while e and m could be interchangeably represent the numbers 2 and 27, 1 and 54, 3 and 18, or 6 and 9. It's possible that c could equal 3, while m and c represent 1 and 6, or 2 and 3. C could be represented by either positive or negative numbers. As it pertains to e and m. They could only both be negative or both be positive, but not 1 of each..

Again, we are not left with a solely whole number valued equation that can make e=mc².

Assuming that both emc2=54 AND e=mc², or emc²=54 and e=mc², fractions and decimals are the only possibilities.

David, I used the numbers on my telephone keypad, squared the c and multiplied and came up with 72, so if Emc2 is correct, welcome all to

Net72