Quote:
Originally Posted by Clark7781
f(x) = ax^3+bx^2+cx+d
find a,b,c,d so that the function has a local maximum at f(-1) = 2 and has a local minimum at f(1) = -1
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a = 0.75
b = 0
c = -2.25
d = 0.5
So,
f(x) = 0.75(x^3)+0(x^2)-2.25x+0.5
(Yes, I did the calculations myself)
Best Regards and Happy Collecting
Craig